A force F is applied to a system of light pulleys to pull body A- If F is 10 kN and block of mass A has a mass of 5 - 103 kg- What is the speed of A after second starting form rest- Assume no friction-A- 4 m - sB- 8 m - sC- 6 m - sD- none of these

The correct option is A 4 m/s F_A=4 ( F/2 )=2F =20KN Acceleration:=F_A/m=20×10^3/5×10^3=4m/s^2 V=u+at=0+4×1=4m/s ...

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Byju's Answer

Standard XII

Physics

Second Law of Motion

A force F is ...

Question

A force F is applied to a system of light pulleys to pull body A. If F is 10 kN and block of mass A has a mass of $5 \times 10^{3}$ kg. What is the speed of A after 1 second starting form rest? Assume no friction.

4 m/s

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8 m/s

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6 m/s

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none of these

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Solution

The correct option is A
4 m/s

$F_{A} = 4 (\frac{F}{2}) = 2 F = 20 K N$
Acceleration:= $\frac{F_{A}}{m} = \frac{20 \times 10^{3}}{5 \times 10^{3}} = 4 m / s^{2}$
$V = u + a t = 0 + 4 \times 1 = 4 m / s$

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A force F is applied to a system of light pulleys to pull body A. If F is 10 kN and block of mass A has a mass of 5×103 kg. What is the speed of A after 1 second starting form rest? Assume no friction.

The correct option is A 4 m/s FA=4(F2)=2F=20KN Acceleration:=FAm=20×1035×103=4m/s2 V=u+at=0+4×1=4m/s

A force F is applied to a system of light pulleys to pull body A. If F is 10 kN and block of mass A has a mass of $5 \times 10^{3}$ kg. What is the speed of A after 1 second starting form rest? Assume no friction.

The correct option is A
4 m/s

$F_{A} = 4 (\frac{F}{2}) = 2 F = 20 K N$
Acceleration:= $\frac{F_{A}}{m} = \frac{20 \times 10^{3}}{5 \times 10^{3}} = 4 m / s^{2}$
$V = u + a t = 0 + 4 \times 1 = 4 m / s$