You visited us 2 times! Enjoying our articles? Unlock Full Access!

Dimensional Analysis

A force F i...

Question

A force $F$ is given by $F = a t + b t^{2}$ , where t is time, the dimensions of $a$ and $b$ are :

[M L T^{- 3}]

and

[M L T^{- 4}]

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

[M L T^{- 3}]

and

[M L^{-} 2 T^{- 4}]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[M L T^{- 4}]

and

[M L T^{1}]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[M L T^{- 3}]

and

[M L^{2} T^{- 4}]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $[M L T^{- 3}]$ and $[M L T^{- 4}]$
From the principle of dimensional homogeneity
$[a] = [\frac{F}{t}] = [M L T^{- 3}]$
$[b] = [\frac{F}{t^{2}}] = [M L T^{- 4}]$

Suggest Corrections

Similar questions

A force F is given by F=at + $b t^{2}$ , where t is time. What are the dimensions of a and b

b t^{2}

a

b

F = a \sqrt{x} + b t^{2}

F

x

t

The dimensions of k in the equation F = - k x (where F is force and x is displacement)

Magnitude of force F experienced by a certain object moving with speed v is given by F = Kv³, where K is a constant. The dimensions of K are

Join BYJU'S Learning Program