CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A force F=K(y^i+x^j), where K is a positive constant, acts on a particle moving in the x - y plane. Starting from the origin, the particle is taken first along the positive x-axis to the point (a,0) and then parallel to the y-axis to the point (a,a). The total work done by the force F on the particle is


Your Answer
A
2Ka2
Your Answer
B
2Ka2
Correct Answer
C
Ka2
Your Answer
D
Ka2

Solution

The correct option is C Ka2
In going from (0,0) to (a,0), the x-coordinate varies from 0 to a while the y-coordinate remains zero.

Work done by force F along this path is (y=0)
W1=a0F.dx=a0(Kx^j).dx^iW1=0
(^j.^i=0)

In going from (a,0) to (a,a), the x-coordinate remains constant at x=a while y-coordinate changes from 0 to a.
Work done by force F along this path is (x=a)


W2=a0F.dy=a0K(y^i+a^j).dy^j
=Kaa0dyW2=Ka2
(^i.^j=0,^j.^j=1)

The total work done is:
W=W1+W2=0Ka2=Ka2.

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More


People also searched for
View More



footer-image