Question

A force is equal to $85.75\text{dyne}$. If it is expressed in $\text{Newton}$, then the number of significant figures will be

• A. $6$
• B. $5$
• C. $3$
• D. $4$

Answer 1

The correct option is D $4$

We know that, $1\text{dyne}={10}^{-5}\text{N}$.
So, $85.75\text{dyne}=85.75\times {10}^{-5}\text{N}$
Also, we know that change in prefixes of unit does not change the number of significant figures.
Thus, the total number of significant figure will be $4$.