A force of 1 megadyne acts on a body and produces a displacement of 50 cm. calculate kinetic energy possessed by the body

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Solution

Dear Student ,
Here in this case ,
$W = F s = \frac{1}{2} m \times 2 a s = \frac{1}{2} m \times v^{2} = K i n e t i c e n e r g y o f t h e b o d y$
So the kinetic energy possessed by the body is equal to the work done by the body.
So the kinetic energy is ,
$E_{k} = 1 \times 10^{6} \times 50 = 5 \times 10^{7} d y n e \cdot c m$
Regards

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A force of 1 megadyne acts on a body and produces a displacement of 50 cm. calculate kinetic energy possessed by the body

Dear Student , Here in this case , W=Fs=12m×2as=12m×v2=Kinetic energy of the body So the kinetic energy possessed by the body is equal to the work done by the body. So the kinetic energy is , Ek=1×106×50=5×107 dyne·cm Regards