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Standard VIII

Physics

Moment of Force

A force of 10...

Question

A force of $10.5 N$ is applied at the end of a circular disc pivoted at center. The diameter of the disc is $0.5 m$ , calculate the amount of torque generated due to this acting force.

$2.525 N m$

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$26.25 N m$

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$2.526 N m$

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$2.625 N m$

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Solution

The correct option is D
$2.625 N m$

Given: $F o r c e F = 10.5 N, D i a m e t e r d = 0.5 m i . e . R a d i u s r = \frac{0.5}{2}$ = $0.25 m, θ = 90 d e g r e e s$ , $as the force is acting tangentially to disc$ .

$We know that,$ $τ = r F s i n θ$

$T h e r e f o r e$ , $τ = 0.25 \times 10.5 \times s i n 90 = 2.625 N m$

$So the torque produced due to the application of$ $10.5 N$ $f o r c e t o a d i s c i s$ $2.625 N m$ .

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A force of 10.5 N is applied at the end of a circular disc pivoted at center. The diameter of the disc is 0.5 m, calculate the amount of torque generated due to this acting force.

A force of $10.5 N$ is applied at the end of a circular disc pivoted at center. The diameter of the disc is $0.5 m$ , calculate the amount of torque generated due to this acting force.