A force of $10.5 N$ is applied at the end of a circular disc pivoted at center. The diameter of the disc is $0.5 m$ , calculate the moment of force generated due to this force.

$2.525 N m$

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$26.25 N m$

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$2.526 N m$

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$2.625 N m$

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Solution

The correct option is D
$2.625 N m$

Given: $F o r c e F = 10.5 N, D i a m e t e r d = 0.5 m i . e . R a d i u s r = \frac{0.5}{2}$ = $0.25 m,$ ,
Perpendicular Distance of the force from the pivot point = 0.25 m
We know that , moment of force = Force $\times$ perpendicular distance of force from the pivot point
$T h e r e f o r e$ , $M o m e n t o f f o r c e = 0.25 \times 10.5 = 2.625 N m$

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A force of 10.5 N is applied at the end of a circular disc pivoted at center. The diameter of the disc is 0.5 m, calculate the moment of force generated due to this force.

A force of $10.5 N$ is applied at the end of a circular disc pivoted at center. The diameter of the disc is $0.5 m$ , calculate the moment of force generated due to this force.