Question

A force of $10N$ acting on a body at an angle of ${60}^0$ with the horizontal direction displaces the body through a distance of $2m$ along the surface of a floor. Calculate the work done. Now let the force or pull acting on the body makes an angle of ${30}^0$ with the horizontal. What is the value of the force to displace the body through $2m$ along the surface of the floor?

Answer 1

Work done in fruit case $=F.S.cos\theta =10\times 2\times \cos 6010J$

Work done in second case is same as $10J=FS\cos \theta \Rightarrow F\times 2\times \cos 30=10F=\frac{10}{\sqrt{3}}N$