A force of $10 N$ acts on a block at an angle of $60^{\circ}$ and because of which it moves by $10 m$ on a frictionless surface. Find the work done by the force on the block.

50 Joules

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25 Joules

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100 Joules

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1 Joules

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Solution

The correct option is A
50 Joules

W = F S cos $θ$
= 10 $\times 10 \times \frac{1}{2}$ = 50 J

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A force of 10 N acts on a block at an angle of 60∘ and because of which it moves by 10 m on a frictionless surface. Find the work done by the force on the block.

The correct option is A 50 Joules W = F S cos θ = 10 ×10×12 = 50 J

A force of $10 N$ acts on a block at an angle of $60^{\circ}$ and because of which it moves by $10 m$ on a frictionless surface. Find the work done by the force on the block.

The correct option is A
50 Joules

W = F S cos $θ$
= 10 $\times 10 \times \frac{1}{2}$ = 50 J