A force of 10 N acts on a body of mass 2 kg for 3 s, initially at rest. calculate : (i) the velocity acquired by the body, and (ii) change in momentum f the body.

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Solution

Force = mass× acceleration
F =10 N
mass = 2 kg
a = F/m = 10/2 = 5 m/s²
i)now, u = 0
t = 3 sec
v = u + at = 0 + 3×5 = 15 m/s
ii) initial momentum = mu = 2×0 =0
final momentum = mv = 2×15 = 30 kg m/s
change in momentum = final momentum - initial momentum
= 30 -0 = 30 kg m/s

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A force of 10 N acts on a body of mass 2 kg for 3 s, initially at rest. calculate : (i) the velocity acquired by the body, and (ii) change in momentum f the body.

Force = mass× acceleration F =10 N mass = 2 kg a = F/m = 10/2 = 5 m/s² i)now, u = 0 t = 3 sec v = u + at = 0 + 3×5 = 15 m/s ii) initial momentum = mu = 2×0 =0 final momentum = mv = 2×15 = 30 kg m/s change in momentum = final momentum - initial momentum = 30 -0 = 30 kg m/s

Force = mass× acceleration
F =10 N
mass = 2 kg
a = F/m = 10/2 = 5 m/s²
i)now, u = 0
t = 3 sec
v = u + at = 0 + 3×5 = 15 m/s
ii) initial momentum = mu = 2×0 =0
final momentum = mv = 2×15 = 30 kg m/s
change in momentum = final momentum - initial momentum
= 30 -0 = 30 kg m/s