A force of $10 N$ acts on a body of mass $20 k g$ for $10 s$ .Change in its momentum is:

5 k g m / s

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100 k g m / s

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200 k g m / s

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1000 k g m / s

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Solution

The correct option is B $100 k g m / s$
$Δ P = F Δ t = 10 \times 10 = 100 k g m / s$
Where,
$Δ$ P = Change in momentum,
F = Applied force
$Δ$ t = time for which force has been applied on the body

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