Question

A force of $10N$ acts on a body towards the east. The work done by the force while the body moves through $1m$ in the east-north direction (midway between east and north) is

• A. $10\sqrt{2}J$
• B. $\frac{10}{\sqrt{2}}J$
• C. $-10J$
• D. $-$$\frac{10}{\sqrt{2}}J$

Answer 1

The correct option is B

$\frac{10}{\sqrt{2}}J$

Step 1: Given data

Given data

Force = $10N$

Displacement = $1m$

Step 2: Calculation for work done

$\theta ={45}^0$( East-north direction)

W = $F\times S\times \cos \theta$

W = $10\times 1\times \cos 45$

W= $10\times 1\times \frac{1}{\sqrt{2}}$

W = $\frac{10}{\sqrt{2}}J$

Hence, option B is correct.