Question

A force of 10 N is required to move a conducting loop through a non-uniform magnetic field at $2{ms}^{-1}$. The rate of production of electrical energy (in watt) in loop is

• A. 5
• B. 20
• C. 10
• D. Zero

Answer 1

The correct option is A 5

We have,

$f=10N$

$velocity=2m/s$

So, the rate of the electrical energy produced in the loop is:

$f=(E+B)v$ Where b is the magnetic field and E is the electrical energy

$10=(E+0)\times 2$

$E=\frac{10}{2}$

$=5W$