MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Inclined Plane

A force of 10...

Question

A force of 10 N making an angle 30^° with positive x-axis acts on a 2 kg block moving in xy plane. Work done by the object as it moves from origin to the point having position vector(2i-4j) is

Open in App

Solution

Suggest Corrections

thumbs-up

0

Similar questions

F = - K (y^i - x^j)

K

is a positive constant) acts on a particle moving in the

X Y -

plane. Starting from the origin, the particle is taken along the positive

X -

axis to the plane

(a, 0)

and then parallel to the

Y -

axis to the point

(a, a)

. The total work done by the force

F

on the particle is

F = - k (y i + x j)

k

is a positive constant) acts on a particle moving in the

x y

- plane. Starting from the origin, the particle is taken along the positive

x

- axis to the point

(a, 0)

and then parallel to the

y

- axis to the point

(a, a)

. The total work done by the force

F

on the particle is

F = - K (y^i + x^j)

K

is a positive constant) acts on a particle moving in the xy-plane. Starting from the origin, the particle is taken along the positive x-axis to the point

(a, 0)

and then parallel to the y-axis to the point

(a, a)

. The total work done by the force

F

on the particles is

\to F = - k (y^i + x^j)

k

is a positive constant) acts on a particle moving in the

x - y

plane. Starting from the origin, the particle is taken along the positive

x -

axis to the point

(a, 0)

and then parallel to the

y -

(a, a)

. Then, total work done by the force is

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Inclined Planes and Screws

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard VI Physics

Join BYJU'S Learning Program

CrossIcon