A force of 10 i-3j-6k N acts on a body of 5 kg and displaces it from A 6i-5j-3km to B10 i-2j-7km- The work done is

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Acceleration Due to Gravity

A force of ...

Question

A force of $(10 ˆ i - 3 ˆ j + 6 ˆ k) N$ acts on a body of 5 kg and displaces it from $A (6 ˆ i + 5 ˆ j - 3 ˆ k) m$ to $B (10 ˆ i - 2 ˆ j + 7 ˆ k) m$ . The work done is

zero

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Similar questions

(10^i - 3^j + 6^k) N

5 kg

A (6^i - 5^j + 3^k) m

B (10^i - 2^j + 7^k) m

\to F = (3 t ˆ i + 5 ˆ j)

\to s = (2 t^{2} ˆ i - 5 ˆ j)

t = 0

2 s e c

\to 10 i - \to 5 j + \to 7 k

A

B

A

B

\to 3 i - \to j + \to 2 k

\to i + \to 3 j + \to 2 k

\to F = (3 t ˆ i + 5 ˆ j)

\to s = (2 t^{2} ˆ i - 5 ˆ j)

t = 0

2 s e c

_{1} = ˆ i - 2 ˆ j + 2 ˆ k

N

_{2} = - 3 ˆ i + ˆ j - 3 ˆ k

N

_{1} = ˆ i - ˆ j

m

_{2} = 2 ˆ j - a ˆ k

m

^{'} a^{'}

5 J

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