A force of $10 N$ acts on a body of mass $2 k g$ for $3 s$ , initially at rest. Calculate:
(i) the velocity acquired by a body
(ii) change in momentum of the body

Open in App

Solution

$Given: F = 10 N, m = 2 k g, t = 3 s$ , Initial velocity, $u = 0$

$Step 1: Acceleration of the body$
$F = m a$
$\Rightarrow a = \frac{F}{m} = \frac{10 N}{2 K g} = 5 m / s^{2}$
$Step 2: Velocity acquired by the body after 3s$
As acceleration is constant, therefore applying equation of motion:
$v = u + a t = 0 + 5 \times 3 = 15 m / s$

$Step 3: Change in momentum$
Change in momentum $=$ Final momentum $-$ Initial momentum
$= m v - m u = m (v - u)$
$= 2 k g (15 m / s - 0)$
$= 30$ $k g$ - $m / s$

Suggest Corrections

Similar questions

A force of 10 Newton acts on a body of mass 2kg for 3seconds initially at rest calculate velocity acquired by the body and change in momentum of the body

A force acts for 10 s on a stationary body of mass 100 kg after which the force cases to act. The body moves through a distance of 100 m in the next 5 s. Calculate:

(i) the velocity acquired by the body
(ii) the acceleration produced by the force, and
(iii) the magnitude of the force.

Q. A force of

10 N

acts on a body of mass

20 k g

for

10 s

.Change in its momentum is:

A force acts for 0.1 sec on a body of mass 2kg initially at rest. The force is then withdrawn and the body moves with a velocity of 2m/s . Find the magnitude of force

Join BYJU'S Learning Program

A force of 10N acts on a body of mass 2kg for 3s, initially at rest. Calculate:(i) the velocity acquired by a body(ii) change in momentum of the body

A force of $10 N$ acts on a body of mass $2 k g$ for $3 s$ , initially at rest. Calculate:
(i) the velocity acquired by a body
(ii) change in momentum of the body