Question

A force of $12N$ pulls a block of mass $3.5kg$ through a rope of mass $0.5kg$. The block is resting on a horizontal frictionless surface. What is the force of reaction exerted by the block on the rope?

Answer 1

Given,

Force applied is $12N$

$a=\frac{F}{m_{total}}$ =$\frac{12}{3.5+.5}$=$\frac{12}{4}$=$3m/s^2$

$Tension=m_{block}\times a$=$3.5\times 3$=$10.5N$

Reaction force = Tension applied on block (In Magnitude)

Reaction force exerted by block is$10N$.