The correct option is B 1620 J
Given,
F=15 N
m=10 kg
t=12 s
u=0 m/s
Acceleration produced due to this force is
a=Fm=1510=1.5 m/s2
Velocity of the object after
12 s is
v=u+at
v=0+1.5×12
⇒ v=18 m/s
Therefore, work done by the force is
⇒ W=△K.E
⇒ W=K.Ef−K.Ei=12mv2−12mu2
⇒ W=12×10×182−0=1620 J