A force of $16 N$ acts on a body at rest having mass $2 k g$ . During this time, the body attains a velocity of $32 m / s$ . The time for which the force acts on the body is

10 s e c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 s e c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7 s e c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 s e c

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $4 s e c$
Given,
$F = 16 N, m a s s = 2 k g, v_{t} = 32 m / s$

To find t at which v_t =32 m/s,

Acceleration=8 m/s,

$v = u + a t$ (u=0, initially at rest)
$32 = 8 t$

$t = 4 s$

Suggest Corrections

Similar questions

Q. A force acts for 1 s on a body of mass 2.0 kg initially at rest. The force is then withdrawn and the body attains a velocity of 2 m/s. Find the magnitude of the force.

Q. A body of mass 2kg having a velocity of 2m/s is brought to rest within a distance of 2m. Find the force acting on the body?

Q. A force acts for

10 sec

on a body of mass

100 kg

which was at rest, after which it ceases to act. If the body travels

160 m

in the next

8 sec

, find the magnitude of the force.

Q. A body of mass

100 g

is at rest on a smooth surface. A force of

0.1 N

starts to act on it for

5 s

. Calculate the distance travelled by the body during this time interval.

A force of 10 Newton acts on a body of mass 2kg for 3seconds initially at rest calculate velocity acquired by the body and change in momentum of the body

Join BYJU'S Learning Program

A force of 16 N acts on a body at rest having mass 2 kg. During this time, the body attains a velocity of 32 m/s. The time for which the force acts on the body is

The correct option is D 4 secGiven,F=16N,mass=2kg,vt=32m/sTo find t at which v_t =32 m/s,Acceleration=8 m/s,v=u+at (u=0, initially at rest) 32=8tt=4s

A force of $16 N$ acts on a body at rest having mass $2 k g$ . During this time, the body attains a velocity of $32 m / s$ . The time for which the force acts on the body is

The correct option is D $4 s e c$
Given,
$F = 16 N, m a s s = 2 k g, v_{t} = 32 m / s$

To find t at which v_t =32 m/s,

Acceleration=8 m/s,

$v = u + a t$ (u=0, initially at rest)
$32 = 8 t$

$t = 4 s$