Question

A force of $1600$ dyne acts on a rigid body, such that the perpendicular distance between force and turning point is $40cm$. Calculate the moment of force.

• A. $4\times {10}^{3}dynecm$
• B. $6\times {10}^{3}dynecm$
• C. $74\times {10}^{3}dynecm$
• D. $64\times {10}^{3}dynecm$

Answer 1

The correct option is D $64\times {10}^{3}dynecm$

Force $F=1600dyne$

Perpendicular distance between force and turning point $r=40cm$

Torque $\tau =rF=40\times 1600=64\times {10}^{3}dynecm$