Question

A force of $2.25N$ acts on a charge of $15\times {10}^{-4}C$. The intensity of electric field at that point is then

• A. $150N{C}^{-1}$
• B. $15N{C}^{-1}$
• C. $1500N{C}^{-1}$
• D. $1.5N{C}^{-1}$

Answer 1

The correct option is C $1500N{C}^{-1}$

Electric field, $E=\frac{F}{q}=\frac{2.25N}{15\times {10}^{-4}C}=1500N{C}^{-1}$