The correct option is D 16 m s−1
Given: force F=20 N, mass m=10 kg and time t=8 s.
Let initial velocity be u, acceleration be a and as body double its velocity in 8 s, final velocity, v=2u.
From, Newton's second law ,we know F=ma=m(v−ut)
Substituting the values, we get,
20=10(v−ut)
2=2u−u8(∵v=2u)
⇒u=16 ms−1
Therefore, initial velocity is 16 ms−1