Question

# A force of $20N$ acts on a body and displaces it $2m$ along the direction of the force. Then the work done by the force is:

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Solution

## Step 1: Given dataForce acting on the body (F) = $20N$Displacement of the body (S) = $2m$Step 2: Formula used$W=F·S\mathrm{cos}\theta$, where W is the work done by the force, F is the force acting on the body, S is its displacement and $\theta$ is the angle between the direction of force and the displacement vector.Step 3: Calculate work doneSince the body is displaced in the direction of the applied force, $\theta =0$. Now, on substituting the given values in the formula, we get: $W=20·2\mathrm{cos}\left(0°\right)\phantom{\rule{0ex}{0ex}}W=20·2·1\phantom{\rule{0ex}{0ex}}W=40J$Thus, the work done by the force will be $40J$.

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