A force of $25 N$ acts on a body at rest for $0.2 s$ and a force of $70 N$ acts for the next $0.1 s$ in opposite direction. If the final velocity of the body is $5 m s^{- 1}$ , the mass of the body is:

1 k g

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2 k g

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0.8 k g

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0.4 k g

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Solution

The correct option is D $0.4 k g$
$25 = m a_{1}$
$u = a_{1} t = \frac{25}{m} 0.2$
$70 = m a_{2}$
$v = u - a_{t}$ $= \frac{25}{m} 0.2$ - $\frac{70}{m} 0.1$
$m = 0.4 k g$

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A force of 25 N acts on a body at rest for 0.2s and a force of 70 N acts for the next 0.1s in opposite direction. If the final velocity of the body is 5ms−1, the mass of the body is:

The correct option is D 0.4 kg25=ma1u=a1t=25m0.270=ma2v=u−at=25m0.2 -70m0.1m=0.4kg

A force of $25 N$ acts on a body at rest for $0.2 s$ and a force of $70 N$ acts for the next $0.1 s$ in opposite direction. If the final velocity of the body is $5 m s^{- 1}$ , the mass of the body is:

The correct option is D $0.4 k g$
$25 = m a_{1}$
$u = a_{1} t = \frac{25}{m} 0.2$
$70 = m a_{2}$
$v = u - a_{t}$ $= \frac{25}{m} 0.2$ - $\frac{70}{m} 0.1$
$m = 0.4 k g$