A force of 25 N25~ N25 N is applied at an angle of 60°60°60°in the direction of displacement. Calculate the amount of work done by the force if the displacement of the block is 5 m5~m5 m.
Given,
Force = F=25N
Displacement = s=5m
Angle between force and displacement = θ=600
We know that, Work done = W=F×s×Cosθ
∴W=25×5×12=62.5J