Question

A force of 250 N is applied to the smaller piston of hydraulic machine. Neglecting friction, find the force exerted on the large piston, if the area of the pistons is $5m^2$ and $25m^2$ respectively.

• A. 1200 N
• B. 1250 N
• C. 1300 N
• D. 1350 N

Answer 1

The correct option is B

1250 N

Given, the force on small piston $F_1=250N$, Area of small piston $A_1=5m^2$ and Area of large piston $A_2=25m^2$. Let the force exerted on the large piston be $F_2$.

According to Pascal law,

$\frac{F_1}{A_1}=\frac{F_2}{A_2}$

On substituting values, $\frac{250}{5}=\frac{F_2}{25}$.

We get $F_2=1250N$. Therefore, the force exerted on the large piston is 1250 N.