A force of $250 N$ is required to lift a $75 k g$ mass through a pulley system. In order to lift the mass through $3 m$ , the rope has to be pulled through $12 m$ . The percent efficiency of system is

50

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75

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33

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90

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Solution

The correct option is B $75$
Height lift was $h = 3 m$
Work done by the force is $W = F d = 250 \times 12 = 3000 J o u l e$

Work against the gravity i.e. $i n c r e a s e$ in potential energy of the mass is $E = m g h = 75 \times 10 \times 3 = 2250 J o u l e$

so efficiency will be $η \times 100 = \frac{E}{W} \times 100$ % = $75$ %

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A force of 250N is required to lift a 75kg mass through a pulley system. In order to lift the mass through 3m, the rope has to be pulled through 12m. The percent efficiency of system is

The correct option is B 75Height lift was h=3mWork done by the force is W=Fd=250×12=3000JouleWork against the gravity i.e. increase in potential energy of the mass is E=mgh=75×10×3=2250Jouleso efficiency will be η×100=EW×100% = 75%

A force of $250 N$ is required to lift a $75 k g$ mass through a pulley system. In order to lift the mass through $3 m$ , the rope has to be pulled through $12 m$ . The percent efficiency of system is