Question

a force of 30 n acts on a rigid body such that perpendicular distance between the force and it's turning point is 30 cm. calculate the moment of force

Answer 1

Dear student,
$$\begin{gathered} Force=30Newton \\ perpendiculardis\tan ce=30cm=\frac{30}{100}m=\frac{3}{10}m \\ momentofforce=forcexperpendiculardis\tan ce=30\times \frac{3}{10}=9Nm \end{gathered}$$
answer: moment of force= 9Nm will be applied when a force of 30 N acts on a rigid body such that perpendicular distance between the force and it's turning point is 30 cm


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