A force of 30N is sufficient just to pull a block of mass 4kg, horizontally over a flat rough surface. The angle of friction is
A
45∘
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B
53∘
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C
37∘
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D
30∘
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Solution
The correct option is C37∘ FBD
For equilibrium R=4g=40N fs=30N
Given that body is just about to slide in this situation, so ∵(f)max=μsR=30 ⇒μs=3040=0.75
From definition; Angle of friction θ=tan−1(μs)=tan−1(0.75)=37∘