A force of $40 N$ exerts a pressure of $800 P a$ on a surface. The area over which the force acts is

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Solution

As $P = \frac{F}{A} \Rightarrow A = \frac{F}{P}$
$A = \frac{40}{800} = \frac{1}{20} m^{2} = \frac{1}{20} \times 10000 = 500 c m^{2}$

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