Question

A force of $40N$ is applied over a surface area of $2.5m^2$ . Calculate the pressure.

Answer 1

Step 1: Given,

Force, $\mathit{F}\mathbf{=}\mathbf{40}\mathit{N}$

Area, $\mathit{A}\mathbf{=}\mathbf{2}\mathbf{.}\mathbf{5}{\mathit{m}}^{\mathbf{2}}$

Step 2: Finding pressure

Pressure can be defined as the force applied per unit area on a body.

Pressure (P)$\mathbf{=}\frac{\mathbf{F}\mathbf{o}\mathbf{r}\mathbf{c}\mathbf{e}\mathbf{\left(}\mathbf{F}\mathbf{\right)}}{\mathbf{A}\mathbf{r}\mathbf{e}\mathbf{a}\mathbf{\left(}\mathbf{A}\mathbf{\right)}}$

Substituting the values in the formula

$$\begin{gathered} \mathit{P}\mathbf{=}\frac{\mathbf{40}}{\mathbf{2}\mathbf{.}\mathbf{5}} \\ \mathit{P}\mathbf{=}\mathbf{16}\mathbf{}\mathit{P}\mathit{a} \end{gathered}$$

So, the pressure exerted is $16Pa.$