A force of 45N is applied on an object to the left. Another force of magnitude 55N is applied on the same object to the left. And the last force of 115N is applied on it to the right. What is the net force ( magnitude and direction ) on the object?

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Solution

Dear student,
$F o r c e t o t h e l e f t = 45 + 55 = 100 N F o r c e t o t h e r i g h t = 115 N = 115 N N e t f o r c e = 115 - 100 = 15 N t o t h e r i g h t$

Regards

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A force of 45N is applied on an object to the left. Another force of magnitude 55N is applied on the same object to the left. And the last force of 115N is applied on it to the right. What is the net force ( magnitude and direction ) on the object?

Dear student, Force to the left = 45+55 = 100 NForce to the right = 115N = 115 NNet force = 115-100 = 15 N to the right Regards

Dear student,
$F o r c e t o t h e l e f t = 45 + 55 = 100 N F o r c e t o t h e r i g h t = 115 N = 115 N N e t f o r c e = 115 - 100 = 15 N t o t h e r i g h t$

Regards