A force of 5 kgf is required to cut a metal sheet. A shears used for cutting the metal sheet has its blades 5 cm long, while its handles are 10 cm long . What effort is needed to cut the sheet ?

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Solution

Load = 5 kgf

Load arm = 5 cm

Effort arm = 10 cm

By principle of lever, Effort arm $\times$ effort = Load arm $\times$ Load

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A force of 5 kgf is required to cut a metal sheet. A shears used for cutting the metal sheet has its blades 5 cm long, while its handles are 10 cm long . What effort is needed to cut the sheet ?

Load = 5 kgf Load arm = 5 cm Effort arm = 10 cm By principle of lever, Effort arm × effort = Load arm × Load

Load = 5 kgf

Load arm = 5 cm

Effort arm = 10 cm

By principle of lever, Effort arm $\times$ effort = Load arm $\times$ Load