A force of 5 N acts on a 15 kg body initially at rest. The work done by the force during the first second of motion of the body is

5 J

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6 J

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Solution

The correct option is B

$W = F s = F \times \frac{1}{2} a t^{2} [f r o m s = u t + \frac{1}{2} a t^{2}]$
$\Rightarrow W = F [\frac{1}{2} (\frac{F}{m}) t^{2}] = \frac{F^{2} t^{2}}{2 m} = \frac{25 \times (1)^{2}}{2 \times 15} = \frac{25}{30} = \frac{5}{6} J$

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A force of 5 N acts on a 15 kg body initially at rest. The work done by the force during the first second of motion of the body is

The correct option is B W=Fs=F×12at2[from s=ut+12at2] ⇒W=F[12(Fm)t2]=F2t22m=25×(1)22×15=2530=56J

The correct option is B

$W = F s = F \times \frac{1}{2} a t^{2} [f r o m s = u t + \frac{1}{2} a t^{2}]$
$\Rightarrow W = F [\frac{1}{2} (\frac{F}{m}) t^{2}] = \frac{F^{2} t^{2}}{2 m} = \frac{25 \times (1)^{2}}{2 \times 15} = \frac{25}{30} = \frac{5}{6} J$