A force of 5 N acts on a body of weight 9.8 N. What is the acceleration produced in $m / s e c^{2}$

49.00 m / s^{2}

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5.00 m / s^{2}

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1.46 m / s^{2}

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0.5 m / s^{2}

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Solution

The correct option is D $5.00 m / s^{2}$
It is given that

$F = 5 N$

$W = 9.8 N$

$∵ W = m g$

$9.8 = m \times 9.8$

$m = 1 K g$

Force

$F = m a . . . . . . . . (1)$

$5 = 1 \times a$

$a = 5 m / s^{2}$

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