A force of 5 N acts on a particle along a direction making an angle of 60∘ with vertical. Its vertical component be
10 N
3 N
4 N
2.5 N
The component of force in vertical direction =F cosθ=F cos 60∘=5×12=2.5 V.
A force of 5 N, making an angle θ with the horizontal, acting on an object displaces it by 0.4 along the horizontal direction. If the object gains kinetic energy of 1J, the horizontal component of the force is