A force of $5 N$ acts on an object. The displacement is perpendicular to the direction of the force. What is the work done?

5 J

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1 J

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100 J

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0 J

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Solution

The correct option is D $0 J$
Work done on an object along a given direction of motion is equal to force times the displacement times the cosine of the angle. No work is done along the direction of motion if the force is perpendicular( since cosine of 90 degrees is zero). Hence work done is 0J.

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A force of 5N acts on an object. The displacement is perpendicular to the direction of the force. What is the work done?

The correct option is D 0JWork done on an object along a given direction of motion is equal to force times the displacement times the cosine of the angle. No work is done along the direction of motion if the force is perpendicular( since cosine of 90 degrees is zero). Hence work done is 0J.

A force of $5 N$ acts on an object. The displacement is perpendicular to the direction of the force. What is the work done?

The correct option is D $0 J$
Work done on an object along a given direction of motion is equal to force times the displacement times the cosine of the angle. No work is done along the direction of motion if the force is perpendicular( since cosine of 90 degrees is zero). Hence work done is 0J.