A force of 5 N is acting on an object. If object moves 5m in the direction opposite to the application of force, what is the work done?
25 J
-25 J
50 J
-50 J
Work done = F * s * cosθ, = 5 * 5 * cos180o
= -25 J
There are two mutually perpendicular forces acting on an object. One force acts in the direction of motion of the object and the direction of other force is perpendicular to the motion. During this interval, the kinetic energy of the body changes from 25 J to 100 J. The work done by the force acting perpendicular to the direction of the object is:
An object of mass 1kg was moving at a speed of 10 ms−1. A constant force acts for 4s on the object and the speed of object becomes 2 ms−1 in opposite direction after the application of force. The force acting on the object have: