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Question

A force of 5N is applied on a 20kg mass at rest. the work done in the third second is:-

A
258J
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B
254J
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C
12J
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D
25J
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Solution

The correct option is A 258J
Displacement in third second = displacement till 3rd second - Displacement till 2nd second
=a232a222=58m (No term of ut because u=0)

Thus work done in third second =5×58=258J

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