A force of 5 N, making an angle $θ$ with the horizontal, acting on an object displaces it by 0.4 along the horizontal direction. If the object gains kinetic energy of 1J, the horizontal component of the force is

1.5 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.5 N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3.5 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.5 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
2.5 N

Work done on the body = K.E gained by the body

$F s c o s θ = 1 \Rightarrow F c o s θ = \frac{1}{s} = \frac{1}{0.4} = 2.5 N$

Suggest Corrections

Similar questions

Q. A force of

5 N

, making an angle

θ

with the horizontal, acting on an object and displaces it by

0.4 m

along the horizontal direction. If the work done by the force is

1 J

, then the horizontal component of the force is

A force of 5 N, making an angle $θ$ with the horizontal, acting on an object displaces it by 0.4 along the horizontal direction. If the object gains kinetic energy of 1J, the horizontal component of the force is

A force of 5 Newton making an angle x with the horizontal acting on an object is displaced by 0.4m along the horizontal direction if the object gains kinetic energy of 1J the horizontal component of the force is...

A force of $7 N$ , making an angle $q$ with the horizantal, acting on an object displaces it by $0.5 m$ along the horizontal direction. If the object gains kinetic energy of $2 J$ , what is the horizontal component of the force?

Q. A force of

7 N

, making an angle with the horizontal, acting on an object displaces it by

0.5 m

along the horizontal direction. If the object gains K.E. of

2 J

, what is the horizontal component of the force? (in N)

Join BYJU'S Learning Program

A force of 5 N, making an angle θ with the horizontal, acting on an object displaces it by 0.4 along the horizontal direction. If the object gains kinetic energy of 1J, the horizontal component of the force is

The correct option is B 2.5 N Work done on the body = K.E gained by the body Fs cosθ=1⇒F cosθ=1s=10.4=2.5N

A force of 5 N, making an angle $θ$ with the horizontal, acting on an object displaces it by 0.4 along the horizontal direction. If the object gains kinetic energy of 1J, the horizontal component of the force is

The correct option is B
2.5 N

Work done on the body = K.E gained by the body

$F s c o s θ = 1 \Rightarrow F c o s θ = \frac{1}{s} = \frac{1}{0.4} = 2.5 N$