A force of 5 N, making an angle $θ$ with the horizontal, acting on an object displaces it by 0.4 along the horizontal direction. If the object gains kinetic energy of 1J, the horizontal component of the force is

1.5 N

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2.5 N

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3.5 N

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4.5 N

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Solution

The correct option is B
2.5 N

Work done on the body = K.E gained by the body

$F s c o s θ = 1 \Rightarrow F c o s θ = \frac{1}{s} = \frac{1}{0.4} = 2.5 N$

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, making an angle with the horizontal, acting on an object displaces it by

0.5 m

along the horizontal direction. If the object gains K.E. of

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, what is the horizontal component of the force? (in N)

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5 N

, making an angle

θ

with the horizontal, acting on an object and displaces it by

0.4 m

along the horizontal direction. If the work done by the force is

1 J

, then the horizontal component of the force is

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A force of 5 N, making an angle θ with the horizontal, acting on an object displaces it by 0.4 along the horizontal direction. If the object gains kinetic energy of 1J, the horizontal component of the force is

The correct option is B 2.5 N Work done on the body = K.E gained by the body Fs cosθ=1⇒F cosθ=1s=10.4=2.5N

A force of 5 N, making an angle $θ$ with the horizontal, acting on an object displaces it by 0.4 along the horizontal direction. If the object gains kinetic energy of 1J, the horizontal component of the force is

The correct option is B
2.5 N

Work done on the body = K.E gained by the body

$F s c o s θ = 1 \Rightarrow F c o s θ = \frac{1}{s} = \frac{1}{0.4} = 2.5 N$