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Question

A force of 5N moves the particle through a distance of 10m. If 25joule of work is performed then the angle between the force and the direction of motion is


A

0°

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B

90°

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C

30°

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D

60°

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Solution

The correct option is D

60°


Step 1: Given data

Work done W=25J

Force, F=5N

Distance, S=10m

Step 2: Calculating the angle

Let the angle required be θ°

The angle is calculated below:

W=FScosθcosθ=WFScosθ=25J5N×10mcosθ=12θ=60°

The angle between the force and the direction of motion is 60°

Hence, option (d) is correct


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