A force of 5 Newton making an angle x with the horizontal acting on an object is displaced by 0.4m along the horizontal direction if the object gains kinetic energy of 1J the horizontal component of the force is...

Open in App

Solution

F = 5 N S = 0.4 m Gain in K.E = Work done W = 1 J = 1 N. m = FScosx = (Fcosx) S = 0.4 (Fcosx)
Horizontal component of force = Fcosx = 1/s
= 1J /(0.4 m) = 2.5 N

Suggest Corrections

Similar questions

A force of 5 N, making an angle $θ$ with the horizontal, acting on an object displaces it by 0.4 along the horizontal direction. If the object gains kinetic energy of 1J, the horizontal component of the force is

A force of $7 N$ , making an angle $q$ with the horizantal, acting on an object displaces it by $0.5 m$ along the horizontal direction. If the object gains kinetic energy of $2 J$ , what is the horizontal component of the force?