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Question

A force of 5 N, making an angle θ with the horizontal, acting on an object and displaces it by 0.4 m along the horizontal direction. If the work done by the force is 1 J, then the horizontal component of the force is

A
1.5 N
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B
2.5 N
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C
3.5 N
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D
4.5 N
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Solution

The correct option is B 2.5 N

Here, the horizontal component of the applied force is Fcosθ
Work done by force on the body = 1 J
Fcosθ(S)=1 J
Fcosθ=10.4 N=2.5 N

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