Question

A force of $5\text{N}$, making an angle $\theta$ with the horizontal, acting on an object and displaces it by $0.4\text{m}$ along the horizontal direction. If the work done by the force is $1\text{J}$, then the horizontal component of the force is

• A. $1.5\text{N}$
• B. $2.5\text{N}$
• C. $3.5\text{N}$
• D. $4.5\text{N}$

Answer 1

The correct option is B $2.5\text{N}$


Here, the horizontal component of the applied force is $F\cos \theta$
Work done by force on the body = $1\text{J}$
$\Rightarrow F\cos \theta \left(S\right)=1\text{J}$
$\therefore F\cos \theta =\frac{1}{0.4}\text{N}=2.5\text{N}$