Question

A force of $5\times {10}^3\text{N}$ is applied on the rod of length $1\text{m}$. Find the linear strain if elongation in the rod is $10\text{mm}$.

• A. $0.1$
• B. $1$
• C. $0.01$
• D. $0.001$

Answer 1

The correct option is C $0.01$

Linear strain is given by $(ϵ=\frac{△l}{l})$
where, $△l=$ change in length of rod due to applied force
$l=$ original length of rod
$ϵ=\frac{10\times {10}^{-3}}{1}={10}^{-2}=0.01$
$ϵ=0.01$