A force of $50 d y n e s$ is acted on a body of mass $5 g$ which is at rest for an interval of $3 s$ , then impulse is:

0.15 \times 10^{- 13} N s

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0.98 \times 10^{- 3} N s

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1.5 \times 10^{- 3} N s

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2.5 \times 10^{- 3} N s

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Solution

The correct option is C $1.5 \times 10^{- 3} N s$
$I m p u l s e J = F Δ t = 50 \times 10^{- 5} \times 3 = 1.5 \times 10^{- 3} N s$

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A force of 50 dynes is acted on a body of mass 5g which is at rest for an interval of 3s, then impulse is:

The correct option is C 1.5×10−3NsImpulseJ=FΔt=50×10−5×3=1.5×10−3Ns

A force of $50 d y n e s$ is acted on a body of mass $5 g$ which is at rest for an interval of $3 s$ , then impulse is:

The correct option is C $1.5 \times 10^{- 3} N s$
$I m p u l s e J = F Δ t = 50 \times 10^{- 5} \times 3 = 1.5 \times 10^{- 3} N s$