A force of $50 d y n e s$ is acted on a body of mass $5 g$ which is at rest for an interval of $3$ seconds, then impulse is (in $N s$ ):

1.5 \times 10^{-} 3

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1.5 \times 10^{-} 2

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2.5 \times 10^{-} 3

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1.5 \times 10^{3}

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Solution

The correct option is B $1.5 \times 10^{-} 3$
Force acting on the body $F = 50 d y n e s = 50 \times 10^{- 5} N$
Time of action of force $t = 3 s$
Thus impulse $I = F t$
$∴ I = 50 \times 10^{- 5} \times 3 = 1.5 \times 10^{- 3} N s$

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A force of 50dynes is acted on a body of mass 5g which is at rest for an interval of 3 seconds, then impulse is (in Ns):

The correct option is B 1.5×10−3Force acting on the body F=50 dynes=50×10−5 NTime of action of force t=3 sThus impulse I=Ft∴ I=50×10−5×3=1.5×10−3 N s

A force of $50 d y n e s$ is acted on a body of mass $5 g$ which is at rest for an interval of $3$ seconds, then impulse is (in $N s$ ):

The correct option is B $1.5 \times 10^{-} 3$
Force acting on the body $F = 50 d y n e s = 50 \times 10^{- 5} N$
Time of action of force $t = 3 s$
Thus impulse $I = F t$
$∴ I = 50 \times 10^{- 5} \times 3 = 1.5 \times 10^{- 3} N s$