Question

A force of $5N$ acts on a particle along a direction making an angle of ${60}^{\circ }$ with vertical. Its vertical component (in newton) is

Answer 1

The component of force in vertical direction
$F_Y=F\cos \theta =F\cos {60}^{\circ }$
$F_Y=5\times \frac{1}{2}$
$F_Y=2.5N$
Final Answer: $2.5N$