A force of $5 N$ is applied on a $20 k g$ mass at rest. The work done in the third second is,

\frac{25}{8} J

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\frac{25}{4} J

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12 J

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25 J

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Solution

The correct option is C $\frac{25}{8} J$
F=ma
5=20a
$a = \frac{1}{4} m / s^{- 2}$
$s_{n} = u + \frac{a}{2} (2 n - 1)$
$s_{3} = \frac{1}{4 \times 2} (2 \times 3 - 1)$
$s_{3} = \frac{5}{8}$
$W_{3} = F s_{3} = \frac{25}{8}$ J

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